(6x^3-x^2+7)/(x+1)

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Solution for (6x^3-x^2+7)/(x+1) equation: 


D( x )

x+1 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:+oo)

(6*x^3-x^2+7)/(x+1) = 0

6*x^3-x^2+7 = 0

6*x^3-x^2+7 = 0

{ 1, -1, 7, -7 }

1

x = 1

6*x^3-x^2+7 = 12

1

-1

x = -1

6*x^3-x^2+7 = 0

-1

x+1

6*x^2-7*x+7

6*x^3-x^2+7

x+1

-6*x^3-6*x^2

7-7*x^2

7*x^2+7*x

7*x+7

-7*x-7

0

6*x^2-7*x+7 = 0

DELTA = (-7)^2-(4*6*7)

DELTA = -119

DELTA < 0

x in { -1} 

x+1 = 0

1 = 0

x belongs to the empty set

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